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12x^2-116x-40=0
a = 12; b = -116; c = -40;
Δ = b2-4ac
Δ = -1162-4·12·(-40)
Δ = 15376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15376}=124$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-116)-124}{2*12}=\frac{-8}{24} =-1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-116)+124}{2*12}=\frac{240}{24} =10 $
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